document.write( "Question 281449: I am about to ask MTV viewers the following question: \"Do you regularly watch MTV's Beavis and Butthead?\" Last week I asked 100 of my friends the same question and 35 of them said yes.
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document.write( "How many actual viewers must be surveyed to be 95% confident that the estimate of the viewership is in error by at most 3%? (Assume 100% response rate.)
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document.write( "What would be your answer if I had not surveyed any of my friends?
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document.write( "Please show details of your work.
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Algebra.Com's Answer #204439 by stanbon(75887) ![]() You can put this solution on YOUR website! How many actual viewers must be surveyed to be 95% confident that the estimate of the viewership is in error by at most 3%? (Assume 100% response rate.) \n" ); document.write( "------------------ \n" ); document.write( "n = [zs/E]^2 \n" ); document.write( "n = [1.96*s/0.03]^2 \n" ); document.write( "---- \n" ); document.write( "You would need to know the standard deviation \n" ); document.write( "of the distribution. \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |