document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=281414>Question 281414</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle is inscribed in a circle of radius 6.5 cm. If the the length of the rectangle is 2 cm longer than twice the width, then the dimensions of the rectangle are:\r<BR>\n" );
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document.write( "(A) 4.5 cm x 11 cm (B) 5 cm x 12 cm (C) 5.5 cm x 13 cm<BR>\n" );
document.write( "(D) 6.5 cm x 12 cm (E) none of these\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204423 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204423\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the width of the rectangle be x\r<BR>\n" );
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document.write( "the length = 2x+2\r<BR>\n" );
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document.write( "the radius =6.5 which is half the diagonal. 6.5 *2 =13 will be diagonal\r<BR>\n" );
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document.write( "the diagonal is the hypotenuse of the triangle with sides x and 2x +2\r<BR>\n" );
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document.write( "x^2+(2x+2)^2=13^2\r<BR>\n" );
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document.write( "x^2+4x^2+8x+4=169\r<BR>\n" );
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document.write( "5x^2+8x-165=0\r<BR>\n" );
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document.write( "5x^2-25x+33x-165=0\r<BR>\n" );
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document.write( "5x(x-5)+33(x-5)=0\r<BR>\n" );
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document.write( "(x-5)(5x+33)=0\r<BR>\n" );
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document.write( "so x = 5 is the width\r<BR>\n" );
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document.write( "length is 2x+2 =12 </SPAN>\n" );
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