document.write( "Question 281408: Lahi invested $5400 in to accounts, one paying 8% and the other paying 10%. If both investments produce the same amount of interest, how much was invested at 8%? \n" ); document.write( "
Algebra.Com's Answer #204415 by subudear(62)\"\" \"About 
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\n" ); document.write( "Lets invest $x at 8% interest then rest of the amount $(5400 - x) will be invested at 10% interest rate.\r
\n" ); document.write( "\n" ); document.write( "Now interest earned on 8% rate will be (8/100)*x
\n" ); document.write( "and interest earned on 10% rate will be (10/100)*(5400 - x)\r
\n" ); document.write( "\n" ); document.write( "But it is given that interest earned are same which means
\n" ); document.write( "(8/100)*x = (10/100)*(5400 - x)\r
\n" ); document.write( "\n" ); document.write( "solving it\r
\n" ); document.write( "\n" ); document.write( "8x = 54000 - 10x
\n" ); document.write( "18x = 54000
\n" ); document.write( "x = 3000\r
\n" ); document.write( "\n" ); document.write( "Therefor amount invested at 8% and 10% are $3000 and $2400 respectively.\r
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