document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=281387>Question 281387</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do we get x by it self in this promble. 5+ln(8x)=23 -2 ln x\r<BR>\n" );
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document.write( "the answer is x= e^6/ 2 .... i dont know how to get x by it self \r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204393 by </B><A HREF=/tutors/aboutme.mpl?userid=subudear><B>subudear(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=subudear><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204393\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given that 5+ln(8x)=23 -2lnx\r<BR>\n" );
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document.write( "Lets simplify this\r<BR>\n" );
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document.write( "ln(8x) + 2ln(x) = 23 - 5<BR>\n" );
document.write( "ln(8x) + ln(x)^2 = 18<BR>\n" );
document.write( "ln(8x*x^2) = 18\r<BR>\n" );
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document.write( "ln(2x)^3 = 18\r<BR>\n" );
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document.write( "3ln(2x) = 18\r<BR>\n" );
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document.write( "ln(2x) = 6\r<BR>\n" );
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document.write( "2x = e^6\r<BR>\n" );
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document.write( "x = (e^6)/2\r<BR>\n" );
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document.write( "I hope this clarifies your doubt. </SPAN>\n" );
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