document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=281386>Question 281386</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of two numbers is 45. the first is 9 less than the second find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204391 by </B><A HREF=/tutors/aboutme.mpl?userid=subudear><B>subudear(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=subudear><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204391\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given that the sum of two numbers is 45<BR>\n" );
document.write( "Let the first number by x<BR>\n" );
document.write( "So the second number should be (45 - x)\r<BR>\n" );
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document.write( "Also it is given that first number is 9 less then the second number<BR>\n" );
document.write( "so it means if we add 9 to first number then it would be equal to second number\r<BR>\n" );
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document.write( "x + 9 = 45 -x\r<BR>\n" );
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document.write( "2x = 45 - 9\r<BR>\n" );
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document.write( "2x = 36\r<BR>\n" );
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document.write( "x = 18\r<BR>\n" );
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document.write( "So first number is 18 and <BR>\n" );
document.write( "second number is (45 - 18)= 27 </SPAN>\n" );
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