document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=281372>Question 281372</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write in standard form the equation of the line that has a slope of 2 and passes through the poing (3,9).<BR>\n" );
document.write( " I think you use the y-y1=m(x-x1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204388 by </B><A HREF=/tutors/aboutme.mpl?userid=subudear><B>subudear(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=subudear><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204388\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You are right you shuld use y - y1 = m(x - x1) to find the line with slope 2 and passing through (3,9)\r<BR>\n" );
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document.write( "given m = 2 and x1 = 3, y1 = 9, replacing the values in equation we get\r<BR>\n" );
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document.write( "y - 9 = 2(x - 3)\r<BR>\n" );
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document.write( "y - 9 = 2x - 6\r<BR>\n" );
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document.write( "y = 2x + 3 </SPAN>\n" );
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