document.write( "Question 281364: Write a quadratic equation having the given numbers as solutions. -3.5, 2.2
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Algebra.Com's Answer #204377 by oberobic(2304)\"\" \"About 
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The general form of a quadratic equation that has been solved is to have two factors that are multiplied. In this case, you're told the solutions are x= -3.5 and x=2.2. So the factored form of the equation would be:
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\n" ); document.write( "(x + 3.5)(x - 2.2) = 0
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\n" ); document.write( "Using FOIL...
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\n" ); document.write( "x^2 -2.2x +3.5x -7.7 = 0
\n" ); document.write( "x^2 + 1.3x - 7.7 = 0
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\n" ); document.write( "multiply by 10 to get rid of the decimals...
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\n" ); document.write( "10x^2 + 13x - 77 = 0
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\n" ); document.write( "Checking this equation using the quadratic formula, you can determine if the solutions are x= -3.5 and x= 2.2...
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"10x%5E2%2B13x%2B-77+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2813%29%5E2-4%2A10%2A-77=3249\".
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\n" ); document.write( " Discriminant d=3249 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-13%2B-sqrt%28+3249+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%2813%29%2Bsqrt%28+3249+%29%29%2F2%5C10+=+2.2\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%2813%29-sqrt%28+3249+%29%29%2F2%5C10+=+-3.5\"
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\n" ); document.write( " Quadratic expression \"10x%5E2%2B13x%2B-77\" can be factored:
\n" ); document.write( " \"10x%5E2%2B13x%2B-77+=+10%28x-2.2%29%2A%28x--3.5%29\"
\n" ); document.write( " Again, the answer is: 2.2, -3.5.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+10%2Ax%5E2%2B13%2Ax%2B-77+%29\"

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\n" ); document.write( "Done
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