document.write( "Question 281267: 4.Solve by Elimination-Multiplication. ( )
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document.write( " 3x-2y=3
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document.write( " -x+y=1 \n" );
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Algebra.Com's Answer #204365 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! The given equations are... \n" ); document.write( "3x -2y = 3 \n" ); document.write( "-x + y = 1 \n" ); document.write( ". \n" ); document.write( "Multiply the second equation by 2 to set up for elimination... \n" ); document.write( ". \n" ); document.write( "-2x + 2y = 2 \n" ); document.write( ". \n" ); document.write( "Then add the two equations... \n" ); document.write( ". \n" ); document.write( "3x -2y = 3 \n" ); document.write( "-2x +2y = 2 \n" ); document.write( "x = 5 \n" ); document.write( ". \n" ); document.write( "Substitute x=5 into first equation to find y... \n" ); document.write( ". \n" ); document.write( "3x - 2y = 3 \n" ); document.write( "3(5) -2y = 3 \n" ); document.write( "15 -2y = 3 \n" ); document.write( "-2y = 3 -15 \n" ); document.write( "y = -12/-2 = 6 \n" ); document.write( ". \n" ); document.write( "Check answer by substituting into the 2nd equation... \n" ); document.write( ". \n" ); document.write( "-x + y = 1 \n" ); document.write( "-5 + 6 = 1 \n" ); document.write( "Correct! \n" ); document.write( ". \n" ); document.write( "Answer: \n" ); document.write( "x = 5 \n" ); document.write( "y = 6 \n" ); document.write( ". \n" ); document.write( "Done \n" ); document.write( " |