document.write( "Question 281249: At 9 P.M. Lucy started to gallop her horse at 20 miles per hour to catch Edmund, who had a three hour head start. If Lucy was still 30 miles behind at 11P.M how fast was Edmund riding? \n" ); document.write( "

Algebra.Com's Answer #204354 by Edwin McCravy(20055) $\"\"$ $\"About$

You can put this solution on YOUR website!
At 9 P.M. Lucy started to gallop her horse at 20 miles per hour to catch Edmund, who had a three hour head start. If Lucy was still 30 miles behind at 11P.M how fast was Edmund riding?
\n" ); document.write( "

\r\n" );
document.write( "\r\n" );
document.write( "           DISTANCE     RATE     TIME\r\n" );
document.write( "Lucy         40          20       2\r\n" );
document.write( "Edmond       5r           r       5\r\n" );
document.write( "\r\n" );
document.write( "Lucy's distance = Edmond's distance - 30\r\n" );
document.write( "\r\n" );
document.write( "             40 = 5r - 30\r\n" );
document.write( "             70 = 5r\r\n" );
document.write( "             14 = r\r\n" );
document.write( "\r\n" );
document.write( "Checking:  Edmond started at 6PM. In the 5 hours up to 11PM, \r\n" );
document.write( "Edmond had traveled 14*5 or 70 miles.  Lucy started at 9PM.\r\n" );
document.write( "In the 2 hours up to 11PM, Lucy had traveled 20*2 or 40 miles,\r\n" );
document.write( "which puts her 30 miles behind Edmond.\r\n" );
document.write( "\r\n" );
document.write( "Edwin

\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );