document.write( "Question 281320: The perimeter of a rectangle is 16 feet. The area of the rectangle is 15 square feet. the Length is greater then the width . What is the Length and the width?
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Algebra.Com's Answer #204350 by mananth(16949)\"\" \"About 
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let length be x\r
\n" ); document.write( "\n" ); document.write( "width =y\r
\n" ); document.write( "\n" ); document.write( "x*y=15\r
\n" ); document.write( "\n" ); document.write( "2x+2y=16\r
\n" ); document.write( "\n" ); document.write( "x+y=8\r
\n" ); document.write( "\n" ); document.write( "x=8-y\r
\n" ); document.write( "\n" ); document.write( "xy=15\r
\n" ); document.write( "\n" ); document.write( "y(8-y)=15\r
\n" ); document.write( "\n" ); document.write( "8y-y^2-15=0\r
\n" ); document.write( "\n" ); document.write( "y^2-8y+15=0\r
\n" ); document.write( "\n" ); document.write( "y^2-5y-3y+15=0\r
\n" ); document.write( "\n" ); document.write( "y(y-5)-3(y-5)=0\r
\n" ); document.write( "\n" ); document.write( "(y-3)(y-5)=0\r
\n" ); document.write( "\n" ); document.write( "y=3 , 5 \r
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\n" ); document.write( "\n" ); document.write( "the sides are 3 & 5 feet\r
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