document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=281327>Question 281327</A>: <I><SPAN STYLE=\"word-break: break-all;\"> factor cube root\r<BR>\n" );
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document.write( "27x^3+125y^3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204348 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204348\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 27x^3+125y^3\r<BR>\n" );
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document.write( "27x^3 = 3^3*x^3 = (3x)^3<BR>\n" );
document.write( "125y^3 = 5^3*y^3 = (5y)^3\r<BR>\n" );
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document.write( "Using the fact that a^3 + b^3 = (a+b)*(a^2-ab+b^2) and substituting 3x for a and 5y for b we have:\r<BR>\n" );
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document.write( "(3x)^3 + (5y)^3 = (3x+3y)*((3x)^2-(3x*5y)+(5y)^2)) =\r<BR>\n" );
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document.write( "3*(x+y)*(9x^2 - 15xy + 25y^2)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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