document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=281331>Question 281331</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A farmer has 3000 feet of fencing available to enclose a rectangular field. What is the maximum area?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204345 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204345\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A farmer has 3000 feet of fencing available to enclose a rectangular field. What is the maximum area?<BR>\n" );
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document.write( "Perimeter = 2(L+W)<BR>\n" );
document.write( "3000 = 2(L+W)<BR>\n" );
document.write( "1500 = L+W<BR>\n" );
document.write( "L = W-1500<BR>\n" );
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document.write( "Area = W*L<BR>\n" );
document.write( "A = W(W-1500)<BR>\n" );
document.write( "A = W^2-1500W<BR>\n" );
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document.write( "Quadratic equation with a = 1, b = -1500<BR>\n" );
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document.write( "Maximum occurs when W = -b/2a = 1500/2 = 750 ft.<BR>\n" );
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document.write( "Since L+W = 1500<BR>\n" );
document.write( "L = 1500-750<BR>\n" );
document.write( "L = 750ft<BR>\n" );
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document.write( "Final Answer: length and width need both be 750'<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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