document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=281312>Question 281312</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two consecutive integers with half of the smaller equual to 4 more than one third of the larger </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204337 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204337\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let one integer be x\r<BR>\n" );
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document.write( "the other will be x+1\r<BR>\n" );
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document.write( "1/2  x = 1/3 *(x+1) +4\r<BR>\n" );
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document.write( "x/2- 4 = 1/3* (x+1)\r<BR>\n" );
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document.write( "(x/2 -4) =1/3(x+1)\r<BR>\n" );
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document.write( "x/2 -4 = x/3  + 1/3\r<BR>\n" );
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document.write( "x/2  - x/3 = 4+1/3\r<BR>\n" );
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document.write( "3x-2x  / 6  = 13/3\r<BR>\n" );
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document.write( "3x=78\r<BR>\n" );
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document.write( "x=26\r<BR>\n" );
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document.write( "the other number is 27\r<BR>\n" );
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