document.write( "Question 281243: The length of a photograph is 1 cm less than twice the width. The area is 45cm squared. Find the dimensions of the photograph. \r
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document.write( "the problem must be solved algebracly using the quadratic formula, factoring or anything like that. thanks \n" );
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Algebra.Com's Answer #204290 by vleith(2983)![]() ![]() ![]() You can put this solution on YOUR website! Let width be w and length be l. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "so either w-5 =0 or 2w+9=o \n" ); document.write( "w = 5 or w = -9/2 \n" ); document.write( "since a distance can't be nagative, width = 5 \n" ); document.write( "so length = 2*5-1 = 9\r \n" ); document.write( "\n" ); document.write( "Does 9*5 = 45?? \n" ); document.write( " |