document.write( "Question 281171: Find three consecutive odd integers such that four times the sum of the last two is two greater than ten times the first. \n" ); document.write( "

Algebra.Com's Answer #204259 by josmiceli(19441) $\"\"$ $\"About$

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The consecutive odd integers are:
\n" ); document.write( " $\"n\"$
\n" ); document.write( " $\"n%2B2\"$
\n" ); document.write( " $\"n+%2B+4\"$
\n" ); document.write( "given:
\n" ); document.write( " $\"4%2A%28n%2B2+%2B+n+%2B+4%29+=+10n+%2B+2\"$
\n" ); document.write( " $\"4%2A%282n+%2B+6%29+=+10n+%2B+2\"$
\n" ); document.write( " $\"8n+%2B+24+=+10n+%2B+2\"$
\n" ); document.write( " $\"2n+=+22\"$
\n" ); document.write( " $\"n+=+11\"$
\n" ); document.write( " $\"n+%2B+2+=+13\"$
\n" ); document.write( " $\"n+%2B+4+=+15\"$
\n" ); document.write( "The numbers are 11,13, and 15
\n" ); document.write( "check:
\n" ); document.write( " $\"4%2A%28n%2B2+%2B+n+%2B+4%29+=+10n+%2B+2\"$
\n" ); document.write( " $\"4%2A%2811%2B2+%2B+11+%2B+4%29+=+10%2A11+%2B+2\"$
\n" ); document.write( " $\"4%2A28+=+110+%2B+2\"$
\n" ); document.write( " $\"112+=+112\"$
\n" ); document.write( "OK \n" ); document.write( "

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