document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34066>Question 34066</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (3x-2)^3=9x^2-6. Did I do this problem right? I just want to make sure before I hand it in.  If not, could you show me what I did wrong?  Thank you.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20419 by </B><A HREF=/tutors/aboutme.mpl?userid=fanism><B>fanism(39)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fanism><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20419\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you cannot simply cube each number seperatly...<BR>\n" );
document.write( "(3x-2)^3<BR>\n" );
document.write( "= (3x-2)(3x-2)(3x-2)<BR>\n" );
document.write( "= (9x^2 - 12x + 4)(3x-2)<BR>\n" );
document.write( "= 27x^3 - 54x^2 + 36x - 8 </SPAN>\n" );
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