document.write( "Question 280872: Two coins contain only dimes and quarters. The total value of the coins in the first bank is $15. In the second bank, there are 15 more dimes than in the first bank and half as many quaRTERS. The total value of the second bank is $10.25. Find the number of dimes in the first bank. \n" ); document.write( "
Algebra.Com's Answer #204151 by dabanfield(803)\"\" \"About 
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Two coins contain only dimes and quarters. The total value of the coins in the first bank is $15. In the second bank, there are 15 more dimes than in the first bank and half as many quaRTERS. The total value of the second bank is $10.25. Find the number of dimes in the first bank.\r
\n" ); document.write( "\n" ); document.write( "Let x be the number of dimes in the first bank. Let y be the number of quarters in the first bank.\r
\n" ); document.write( "\n" ); document.write( "The number of dimes in the second bank then is x+15. The number for quarters in the second bank is .5*y.\r
\n" ); document.write( "\n" ); document.write( "So we have:\r
\n" ); document.write( "\n" ); document.write( "First Bank amount:\r
\n" ); document.write( "\n" ); document.write( "1.) .10*x + .25y = 15.00\r
\n" ); document.write( "\n" ); document.write( "Second Bank amount:\r
\n" ); document.write( "\n" ); document.write( "2.) .10*(x+15) + .25*(.5*y) = 10.25\r
\n" ); document.write( "\n" ); document.write( "Solve this system of equations for x.
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