document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=280882>Question 280882</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a triangle is 47 meters. The longest side is 3 times the shortest side. The third side is 2 meters shorter than the longest side. How long is each side? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204149 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204149\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a triangle is 47 meters. The longest side is 3 times the shortest side. The third side is 2 meters shorter than the longest side. How long is each side?\r<BR>\n" );
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document.write( "Let x be the length of the shortest side. Then the three sides are x, 3x and 3x-2.\r<BR>\n" );
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document.write( "The perimeter is 47 so:\r<BR>\n" );
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document.write( "x + 3x + (3x-2) = 47\r<BR>\n" );
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document.write( "Solve the above equation for x and then calculate 3x and 3x-2. </SPAN>\n" );
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