document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34061>Question 34061</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits of a two-digit number is 9. If the digits are reversed, the new number is 27 less than the original. Find the original number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20414 by </B><A HREF=/tutors/aboutme.mpl?userid=fanism><B>fanism(39)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fanism><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20414\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> assume the first digit is x and second digit is y<BR>\n" );
document.write( "Since the sum of the digits of a two-digit number is 9, therefore<BR>\n" );
document.write( "x + y = 9 -- eq1<BR>\n" );
document.write( "it says if the digits are reversed, the new number is 27 less than the original.<BR>\n" );
document.write( "since we are looking at the number like xy, to seperate them, it is actually 10x+y for x is a tens digit.<BR>\n" );
document.write( "10y + x = 10x + y + 27<BR>\n" );
document.write( "simplify it, u will get:<BR>\n" );
document.write( "9y = 9x + 27<BR>\n" );
document.write( "y = x + 3 -- eq2<BR>\n" );
document.write( "sub eq2 into eq1, u will have<BR>\n" );
document.write( "x + (x + 3) = 9<BR>\n" );
document.write( "2x + 3 = 9<BR>\n" );
document.write( "2x = 6<BR>\n" );
document.write( "x = 3<BR>\n" );
document.write( "put back into eq1,<BR>\n" );
document.write( "3 + y = 9<BR>\n" );
document.write( "y = 6\r<BR>\n" );
document.write( "\n" );
document.write( "The original number is 36. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );