document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=280949>Question 280949</A>: <I><SPAN STYLE=\"word-break: break-all;\"> To number the pages of a volume, 3001 digits were printed. Assuming all pages are<BR>\n" );
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document.write( "(A) 1021 (B) 1026 (C) 1027 (D) 1028 (E) none of these<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204122 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204122\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> page numbers 1 to 9 = 1 digit per page * 9 pages = 9 digits total.<BR>\n" );
document.write( "page numbers 10 to 99 = 2 digits per page * 90 pages = 180 digits total.<BR>\n" );
document.write( "page numbers 100 to 999 = 3 digits per page * 900 pages = 2700 digits total.<BR>\n" );
document.write( "page numbers 1000 to 9999 = 4 digits per page * 9000 pages = 36000 digits total.\r<BR>\n" );
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document.write( "Since the total number of digits is 3001, then:\r<BR>\n" );
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document.write( "we ate up 9 digits to get from 1 to 9.<BR>\n" );
document.write( "we ate up another 180 digits to get from 10 to 99.<BR>\n" );
document.write( "we ate up another 2700 digits to get from 100 to 999.\r<BR>\n" );
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document.write( "So far we used a total of 2700 + 180 + 9 = 2889 digits.\r<BR>\n" );
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document.write( "Since we need to eventually use a total of 3001 digits, we have 3001 - 2889 = 112 more digits to go, and all of these digits will have 4 digits per page.\r<BR>\n" );
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document.write( "If we divide 112 by 4, we get 28 pages to go.\r<BR>\n" );
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document.write( "999 + 28 = 1027 pages in the volume.\r<BR>\n" );
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document.write( "If I am correct, that would be selection C.\r<BR>\n" );
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document.write( "The fact that 112 divided evenly by 4 was a good sign.\r<BR>\n" );
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document.write( "I would go with selection C.\r<BR>\n" );
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document.write( "A built in assumption is that the page numbers start at 1 and not 0.\r<BR>\n" );
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document.write( "this is a fair assumption I believe.\r<BR>\n" );
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