document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=280861>Question 280861</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the domain of f(x)=-&#8730;3-2x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204099 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204099\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Is 3-2x under the root symbol? If so:\r<BR>\n" );
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document.write( "Note that square root functions are always greater than or equal to 0.\r<BR>\n" );
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document.write( "-sqrt(3-2x)>=0.\r<BR>\n" );
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document.write( "For it to equal zero we need 3-2x=0 <BR>\n" );
document.write( "so 3/2-x. This is where we will plot the first point in a graph. Second, we note that the negative square root function will be a reflection over the x-axis, this has no effect on the domain.\r<BR>\n" );
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document.write( "Now we need 3-2x>0 so this means -2x>-3 which implies x<3/2. So you now have enough information to graph this function.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+-sqrt%283-2x%29%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+-sqrt%283-2x%29%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "And the domain is read clearly as (-infinity,3/2] </SPAN>\n" );
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