document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=280833>Question 280833</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Assume the body temperatures of healthy adults are normally distributed with a mean of 98.20 degrees fahrenheit and a standard deviation of 0.62 degrees fahrenheit<BR>\n" );
document.write( "a) what is your percentile score if your body temp is 99.0 degrees fahrenheit?<BR>\n" );
document.write( "b) convert 99.00 degrees fahrenheit to a standart score (z-score)<BR>\n" );
document.write( "c) Is a body temperature of 99.0 degrees fahrenheit unusual? Why or why not?<BR>\n" );
document.write( "d)50 adults are randomly selected. What is the likelihood that the mean of their body temperatures is 97.98 degrees fahrenheit or lower?<BR>\n" );
document.write( "e) A person's body temperature is found to be 101.00 degrees fahrenheit. Is the result unusual? Why or why not? What should you conclude?<BR>\n" );
document.write( "f)What body temperature is the 95th percentile?<BR>\n" );
document.write( "g) What body temperature is the 5th percentile?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204095 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204095\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assume the body temperatures of healthy adults are normally distributed with a mean of 98.20 degrees fahrenheit and a standard deviation of 0.62 degrees fahrenheit<BR>\n" );
document.write( "a) what is your percentile score if your body temp is 99.0 degrees fahrenheit?<BR>\n" );
document.write( "z(99) = (99-98.2)/0.62 = 1.2903<BR>\n" );
document.write( "P(z < 1.2903) = 90.15<BR>\n" );
document.write( "99 degrees is at the 90th %ile<BR>\n" );
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document.write( "b) convert 99.00 degrees fahrenheit to a standart score (z-score)<BR>\n" );
document.write( "Done above<BR>\n" );
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document.write( "c) Is a body temperature of 99.0 degrees fahrenheit unusual? Why or why not?<BR>\n" );
document.write( "It's 1.29 standard deviations above the mean: not too unusual.<BR>\n" );
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document.write( "d)50 adults are randomly selected. What is the likelihood that the mean of their body temperatures is 97.98 degrees fahrenheit or lower?<BR>\n" );
document.write( "z(97.98) = (97.98-98.2)/[0.62/sqrt(50)] = -2.5091<BR>\n" );
document.write( "P(xbar<97.98) = P(z<-2.509) = 0.0061<BR>\n" );
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document.write( "e) A person's body temperature is found to be 101.00 degrees fahrenheit. <BR>\n" );
document.write( "Is the result unusual? Why or why not? What should you conclude?<BR>\n" );
document.write( "Find the z-value of 101 and draw your conclusion.<BR>\n" );
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document.write( "f)What body temperature is the 95th percentile?<BR>\n" );
document.write( "Find the z-value that has a 95% left tail: invNorm(0.95) = 1.645<BR>\n" );
document.write( "Find the corresponding x-value:<BR>\n" );
document.write( "x = zs+u<BR>\n" );
document.write( "x = 1.645*0.62+98.2 = 99.22 degrees<BR>\n" );
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document.write( "g) What body temperature is the 5th percentile?<BR>\n" );
document.write( "Follow the same pattern used for \"f\".<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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