document.write( "Question 280830: the perimeter of a rectangle is 132 inches. The length exceeds the width by 46 inches. Find the length and width. \n" ); document.write( "
Algebra.Com's Answer #204092 by oberobic(2304)\"\" \"About 
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Perimeter of a rectangle = 2*length + 2*width.
\n" ); document.write( "l = length
\n" ); document.write( "w = width
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\n" ); document.write( "P = 132 :: given
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\n" ); document.write( "l = w+46 :: given
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\n" ); document.write( "Substituting into the perimeter equation...
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\n" ); document.write( "2l + 2w = 132
\n" ); document.write( "2(w+46) + 2w = 132
\n" ); document.write( "2w + 92 + 2w = 132
\n" ); document.write( "4w + 92 = 132
\n" ); document.write( "4w = 40
\n" ); document.write( "w = 10
\n" ); document.write( ".
\n" ); document.write( "l = w+46 = 56
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\n" ); document.write( "Checking this answer...
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\n" ); document.write( "P = 2*56 + 2*10
\n" ); document.write( "P = 112 + 20
\n" ); document.write( "P = 132
\n" ); document.write( "Correct.
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\n" ); document.write( "Answer:
\n" ); document.write( "Length = 56
\n" ); document.write( "Width = 10
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\n" ); document.write( "Done
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