document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=280773>Question 280773</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much water should be added to 30gallons of a solution that is 70% antifreeze in order to get a mixture that is 60% antifreeze? thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204068 by </B><A HREF=/tutors/aboutme.mpl?userid=Grinnell><B>Grinnell(63)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Grinnell><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204068\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 30(.70)=(30+x).60<BR>\n" );
document.write( "x is the amount of water added, in gallons.<BR>\n" );
document.write( "30 +x is the final amount of solution, in gallons.<BR>\n" );
document.write( "Again we multiply by 100, removing the decimal.<BR>\n" );
document.write( "2100=1800+60x<BR>\n" );
document.write( "300=60x<BR>\n" );
document.write( "5=x so  5 gallons should be added. </SPAN>\n" );
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