document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=280802>Question 280802</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 6 inches less than one-half the length.  Find the length and the width of the rectangle if the perimeter of the rectangle is 72 inches. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204055 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204055\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> w = width<BR>\n" );
document.write( "l = length<BR>\n" );
document.write( "w = 1/2*l - 6<BR>\n" );
document.write( "P = 2(l+w) = 72<BR>\n" );
document.write( "2l + 2w = 72<BR>\n" );
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document.write( "substitute w = 1/2*l -6<BR>\n" );
document.write( ".<BR>\n" );
document.write( "2l + 2w= 72<BR>\n" );
document.write( "2l + 2(1/2*l - 6) = 72<BR>\n" );
document.write( "2l + l - 12 = 72<BR>\n" );
document.write( "3l = 84<BR>\n" );
document.write( "l= 28<BR>\n" );
document.write( ".<BR>\n" );
document.write( "w = 1/2*l -6 = 1/2*28 - 6 = 14-6 = 8<BR>\n" );
document.write( ".<BR>\n" );
document.write( "checking<BR>\n" );
document.write( "2l + 2w = 72?<BR>\n" );
document.write( "2l = 2*28 = 56<BR>\n" );
document.write( "2w = 2*8 = 16<BR>\n" );
document.write( "56+16= 72<BR>\n" );
document.write( "Correct.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Answer:<BR>\n" );
document.write( "length = 28<BR>\n" );
document.write( "width = 8<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Done </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );