document.write( "Question 280764: Using the substitution method {x/8-y/5=1, x/6-y=5} \n" ); document.write( "
Algebra.Com's Answer #204051 by PRMath(133)![]() ![]() ![]() You can put this solution on YOUR website! Using the substitution method {x/8-y/5=1, x/6-y=5}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I would first get rid of the denominators. For the first equation, multiply everything by 40 (which I found by multiplying the denominator 8 by the denominator 5)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "40 \n" ); document.write( "5x - 8y = 40 This is the new first equation. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I would get rid of the denominator 6 in the 2nd equation by multiplying everything by 6. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6 \n" ); document.write( "x -6y = 30 This is the new second equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here are the two equations now:\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5x - 8y = 40 \n" ); document.write( "x -6y = 30 <----- now let's take this equation and solve for \"x\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x - 6y = 30 \n" ); document.write( "x = 6y + 30 (added 6y to both sides to isolate the x) \n" ); document.write( "Now that we know that \"x\" is equal to 6y + 30, let's \"plug\" that into the first equation. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5x - 8y = 40 First equation \n" ); document.write( "5(6y + 30) -8y =40 Plugged in 6y + 30 for the \"x\" variable. \n" ); document.write( "30y + 150 - 8y =40 Distributed 5 to 6y and 5 to 30. \n" ); document.write( "22y + 150 = 40 Combined like terms: 30y - 8y = 22y \n" ); document.write( "22y = 40 - 150 Subtracted 150 from both sides to begin to isolate the y \n" ); document.write( "22y = -110 Found -110 by determining 40 - 150. \n" ); document.write( "y = -5 Divided both sides by 22 to isolate the y. -110 divided by +22 equals -5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now we know that y = -5. Let's plug that into our 2nd equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x -6y = 30 Second equation \n" ); document.write( "x -6(-5) = 30 Plugged -5 in for the \"y\" variable. \n" ); document.write( "x + 30= 30 Determined 30 because -6 times -5 = 30 \n" ); document.write( "x = 30 - 30 Subtracted 30 from both sides to isolate the \"x\" \n" ); document.write( "x = 0.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now we have x = 0 and we have y = -5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's check:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Original equations:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We have proved the answers. I hope this helps you. :-) \n" ); document.write( " |