document.write( "Question 280655: 2 questions:\r
\n" ); document.write( "\n" ); document.write( "if a= b+2, then (b-a)^4 = ?
\n" ); document.write( "-16,-8,1, 8, 16 are the choices\r
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\n" ); document.write( "\n" ); document.write( "which of the following is the set of all real numbers x such that x + 3 > x + 5
\n" ); document.write( "empty set, set containing all real number, set containing all negative real numbers, set containing all nonnegative real numbers or the set containing only zero\r
\n" ); document.write( "\n" ); document.write( "this is for an ACT practice sheet for a 10th grader in algebra II \n" ); document.write( "

Algebra.Com's Answer #204019 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
First take $\"a=+b%2B2\"$ and isolate $\"b-a\"$ to get $\"b-a=-2\"$ . Now raise both sides to the 4th power to get $\"%28b-a%29%5E4=%28-2%29%5E4\"$ . I'll let you carry out the rest of the computations.\r
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\n" ); document.write( "\n" ); document.write( "If we subtract 'x' from both sides on $\"x+%2B+3+%3E+x+%2B+5\"$ , we get $\"3%3E5\"$ which is NEVER true for any value of 'x'. So there are NO solutions. This means that the solution set is the empty set. Recall that the empty set is the set with no elements. \n" ); document.write( "

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