document.write( "Question 280629: graph the equation using the slope and the y intercept
\n" ); document.write( "y=8/3x + 3 \n" ); document.write( "

Algebra.Com's Answer #203971 by oberobic(2304) $\"\"$ $\"About$

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The presented problem is in slope-intercept form: y = mx + b.
\n" ); document.write( "m = slope
\n" ); document.write( "b = y-intercept.
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\n" ); document.write( "y = 8/3x +3
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\n" ); document.write( "slope = 8/3
\n" ); document.write( "y-intercept = 3
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\n" ); document.write( "which defines the point (0,3)
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\n" ); document.write( "We know the slope = rise / run = change in y / change in x.
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\n" ); document.write( "So for every change of 3 in x, we have a change of 8 in y.
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\n" ); document.write( "That allows us to define another point: (0+3, 8+8) or (3,16)
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\n" ); document.write( "You can graph the line using the two points, so pick the x-intercept as another.
\n" ); document.write( "The x-intercept is where y=0.
\n" ); document.write( "0 = 8/3x +3
\n" ); document.write( "-8/3x = 3
\n" ); document.write( "-8x = 9
\n" ); document.write( "x = -9/8
\n" ); document.write( "thus defining the point (-9/8,0)
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\n" ); document.write( " $\"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C8%2F3%2Ax%2B3%29\"$
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