document.write( "Question 280564: Graph the equation and identify the y-intercept: 4y+5x= -12. The y-intercept is? \n" ); document.write( "
Algebra.Com's Answer #203944 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! First, get the equation into slope-intercept form: y = mx + b \n" ); document.write( "4y + 5x = -12 \n" ); document.write( "subtract 5x from both sides \n" ); document.write( "4y = -5x -12 \n" ); document.write( "divide both sides by 4 \n" ); document.write( "y = -5/4x -12/3 \n" ); document.write( "y = -5/4x -4 \n" ); document.write( ". \n" ); document.write( "Recall, \n" ); document.write( "the x-intercept is the point where y=0 and \n" ); document.write( "the y-intercept is the point where x=0. \n" ); document.write( "Thinking visually, the point (0, ??) will be on y-axis somewhere; likewise the point (??, 0) will be on the x-axis somewhere. Since we're drawing a line, it will cross at these points. \n" ); document.write( ". \n" ); document.write( "To find the y-intercept, simply set x=0: \n" ); document.write( "the y-intercept is -4, which is at the point (0,-4) \n" ); document.write( ". \n" ); document.write( "Thinking about the slope-intercept equation, we know the slope is the coefficient of x. \n" ); document.write( "In this case the slope is -5/4, which means it slopes downward from the upper left to the lower right. \n" ); document.write( "We can find the x-intercept by setting y=0 and working it out. \n" ); document.write( "0 = -5/4x -4 \n" ); document.write( "adding 5/4x to both sides \n" ); document.write( "5/4x = -4 \n" ); document.write( "multiply both sides by 4 \n" ); document.write( "5x = -16 \n" ); document.write( "divide both sides by 5 \n" ); document.write( "x = -16/5 \n" ); document.write( "so the x-intercept is (-16/5, 0) \n" ); document.write( ". \n" ); document.write( "Now you have two points: (0,-4) and (-16/5,0). \n" ); document.write( "With two points you can draw line. \n" ); document.write( "Plot the two points and graph the equation. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "A good check is to find another point and verify it is on the line. \n" ); document.write( "Say x= -4, which neatly cancels the denominator... \n" ); document.write( "y = -5/4(-4) -4 \n" ); document.write( "y = 20/4 -4 \n" ); document.write( "y = 5 -4 \n" ); document.write( "y = 1 \n" ); document.write( ". \n" ); document.write( "Is the point (-4,1) on the line? \n" ); document.write( "Yes, it is. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |