document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=280492>Question 280492</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Amy invests a part of $8000 in bonds paying 12% interest. The remainder is in a savings account at 8%. If she receives $840 in interest for 1 year, how much does she have invested at each rate? (Show the two variable equations used to solve it and then the solution)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #203881 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=203881\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let her invest x at 8%<BR>\n" );
document.write( "and y at 12%\r<BR>\n" );
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document.write( "0.08x+0.12y=845<BR>\n" );
document.write( "x+y=8000\r<BR>\n" );
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document.write( "0.08x+0.08y==640\r<BR>\n" );
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document.write( "0.04y=205\r<BR>\n" );
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document.write( "y=5125\r<BR>\n" );
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document.write( "x=8000-5125=2875\r<BR>\n" );
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document.write( " </SPAN>\n" );
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