document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=280500>Question 280500</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In last Saturday’s parade,Tom counted a total of 76 bicycles and<BR>\n" );
document.write( "tricycles, for a total of 227 wheels. How many tricycles were in<BR>\n" );
document.write( "the parade? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #203880 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=203880\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> letthe number of tricycles be x\r<BR>\n" );
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document.write( "the number of bicycles will be 76-x\r<BR>\n" );
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document.write( "3x+2(76-x)=227\r<BR>\n" );
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document.write( "3x+152-2x=227\r<BR>\n" );
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document.write( "x=227-152\r<BR>\n" );
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document.write( "x=75\r<BR>\n" );
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document.write( "bicycles will be 76-75= 1 </SPAN>\n" );
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