document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=280482>Question 280482</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a square and rectangle have the same area. the length of the rectangle is 8 less than twice the side of the square. the width of the rectangle is 3 less than the side of the square. let x represent the length of the side of the square. a)write expressions for the dimensions of the rectangle. b) write an equation that represents the situation. c) find the dimension of the square and rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #203871 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=203871\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> l=2s-8<BR>\n" );
document.write( "w=s-3<BR>\n" );
document.write( "(2s-8)*(s-3)=s^2<BR>\n" );
document.write( "2s^2-8s-6s+24=s^2<BR>\n" );
document.write( "s^2-14s+24=0<BR>\n" );
document.write( "(s-12)*(s-2)=0<BR>\n" );
document.write( "s=12<BR>\n" );
document.write( "s=2<BR>\n" );
document.write( "l=2s-8<BR>\n" );
document.write( "l=24-8=16<BR>\n" );
document.write( "w=9<BR>\n" );
document.write( "16*9=144<BR>\n" );
document.write( "12^2=144\r<BR>\n" );
document.write( "\n" );
document.write( "s=2 can't be since s-3=-1 we can'tr have a negative number for a side\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );