document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34037>Question 34037</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0131411160/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> how do I get x alone to solve it? 3(x-4)=2(x-8)+5x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20386 by </B><A HREF=/tutors/aboutme.mpl?userid=xcentaur><B>xcentaur(357)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=xcentaur><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20386\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3(x-4)=2(x-8)+5x<BR>\n" );
document.write( "open the brackets<BR>\n" );
document.write( "3x-12=2x-16+5x<BR>\n" );
document.write( "3x-12=7x-16<BR>\n" );
document.write( "taking everything to one side<BR>\n" );
document.write( "3x-12-7x+16=0<BR>\n" );
document.write( "remember on taking terms to the other side,their sign reverses<BR>\n" );
document.write( "now we get<BR>\n" );
document.write( "-4x+4=0<BR>\n" );
document.write( "-4x=-4<BR>\n" );
document.write( "x=1<BR>\n" );
document.write( "<P><BR>\n" );
document.write( "xC </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );