document.write( "Question 280461: Find the value of x in:\r
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Algebra.Com's Answer #203853 by user_dude2008(1862)\"\" \"About 
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2^(2x) -2^(x+1) -15 = 0 \r
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\n" ); document.write( "\n" ); document.write( "(2^x)^2 -2*2^x -15 = 0 \r
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\n" ); document.write( "\n" ); document.write( "z^2-2z-15=0\r
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\n" ); document.write( "\n" ); document.write( "(z-5)(z+3)=0\r
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\n" ); document.write( "\n" ); document.write( "z-5=0 or z+3=0\r
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\n" ); document.write( "\n" ); document.write( "z=5 or z=-3\r
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\n" ); document.write( "\n" ); document.write( "2^x=5 or 2^x=-3\r
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\n" ); document.write( "\n" ); document.write( "2^x=-3 ----> no solution\r
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\n" ); document.write( "\n" ); document.write( "2^x=5 ----> \r
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