document.write( "Question 280462: This one looked easy but it's got me confused please help and thank you.
\n" ); document.write( "Use the laws of logarithms to express log base2 6 - log base 2 3 + 2 log base 2 sqrt8 as a single logarithm then evaluate. I got this far log base 2^6 - log base2^3 +2 log base 2 sqrt 8 =log base 2 6/3 sqrt8^2??? help \n" ); document.write( "

Algebra.Com's Answer #203850 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"log%282%2C6%29+-+log%282%2C3%29+%2B+2%2Alog%282%2Csqrt%288%29%29\"$
\n" ); document.write( "The 1st 2 terms are:
\n" ); document.write( " $\"log%282%2C6%29+-+log%282%2C3%29+=+log%282%2C6%2F3%29\"$
\n" ); document.write( " $\"log%282%2C6%2F3%29+=+log%282%2C2%29\"$
\n" ); document.write( " $\"log%282%2C2%29+=+1\"$
\n" ); document.write( "So far I have
\n" ); document.write( " $\"1+%2B+2%2Alog%282%2Csqrt%288%29%29+=+1+%2B+log%282%2C%28sqrt%288%29%29%5E2%29\"$
\n" ); document.write( " $\"1+%2B+log%282%2C%28sqrt%288%29%29%5E2%29+=+1+%2B+log%282%2C8%29\"$
\n" ); document.write( " $\"1+%2B+log%282%2C8%29+=+1+%2B+3\"$
\n" ); document.write( " $\"1+%2B+3+=+4\"$ \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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