document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=280372>Question 280372</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the measure of two complementry angles is 90 degrees. If one angle measures 12 degrees more than twice the measure of the other, find the smaller angle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #203826 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=203826\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+2X+12=90<BR>\n" );
document.write( "3X=90-12<BR>\n" );
document.write( "3X=78<BR>\n" );
document.write( "X=78/3<BR>\n" );
document.write( "X=26 DEGREES FOR THE SMALLER ANGLE.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "26+2*26+12=90<BR>\n" );
document.write( "26+52+12=90<BR>\n" );
document.write( "90=90 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );