document.write( "Question 280373: Two truckdrivers leave a cafe at the same time, traveling in opposite directions. One truck goes 3 mph faster then the other one. After four hours they are 388 miles apart. How fast is each truck going? \n" ); document.write( "
Algebra.Com's Answer #203823 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "388=(R+R+3)4 \n" ); document.write( "388=(2R+3)4 \n" ); document.write( "388=8R+12 \n" ); document.write( "8R=388-12 \n" ); document.write( "8R=376 \n" ); document.write( "8=376/8 \n" ); document.write( "R=47 MPH FOR THE SLOWER TRUCK. \n" ); document.write( "47+3=50 MPH FOR THE FASTER TRUCK. \n" ); document.write( "PROOF: \n" ); document.write( "388=(47+50)4 \n" ); document.write( "388=97*4 \n" ); document.write( "388=388 \n" ); document.write( " |