document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=280396>Question 280396</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boy swims downstream 0.9 miles in the same amount of time that he can swim 0.6 miles upstream. If the rate of the current is 1.5 mph, how fast can he swim in still water? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #203801 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=203801\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( ".9=(R+1.5)T SWIMMING DOWNSTREAM.<BR>\n" );
document.write( "T=.9/(R+1.5)<BR>\n" );
document.write( ".6=(R-1.5)T SWIMMING UPSTREAM.<BR>\n" );
document.write( "T=.6/(R-1.5)<BR>\n" );
document.write( "THE TIMES ARE THE SAME THUS SET THE TWO EQUATIONS EQUAL.<BR>\n" );
document.write( ".9/(R+1.5)=.6/(R-1.5) CROSS MULTIPLY.<BR>\n" );
document.write( ".9(R-1.5)=.6(R+1.5)<BR>\n" );
document.write( ".9R-1.35=.6R=+.9<BR>\n" );
document.write( ".9R-.6R=.9+1.35<BR>\n" );
document.write( ".3R=2.25<BR>\n" );
document.write( "R=2.25/.3<BR>\n" );
document.write( "R=7.5 MPH IS THE SPEED OF THE SWIMMER IN STILL WATER.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( ".9/(7.5+1.5)=.6(7.5-1.5)<BR>\n" );
document.write( ".9/9=.6/6<BR>\n" );
document.write( ".1=.1 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );