document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=280420>Question 280420</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi I've just started working on my conics unit. I really thought I understood how to get an equation from a circle and vise versa BUT then I started to work in my module and got this question. Determine the standard form of the equation of a circle with a center at(4,-1) and passing through(0,2). By looking at the center points I can write part of the equation. (x-4)^2 +(y+1)^2 but I have no radius or diagram of circle to get radius from so would it therefore be 1 or is this where the(0,2) comes in??? I'm not sure what or how I'm suppose to use the(0,2). Could you please explain and thanks so very much. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #203793 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=203793\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the radius is the distance from the center to the circle edge<BR>\n" );
document.write( "you have the center 4,-1 and a point on the circle 0,2<BR>\n" );
document.write( "find the distance .<BR>\n" );
document.write( "That is the radius<BR>\n" );
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