document.write( "Question 280404: A women invested 4 times as much at 5% as she did at 6%. The total amount of interest she earns in 1 year from both accounts is $520. How much did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #203788 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .05*4x+.06x=520 \n" ); document.write( ".20x+.06x=520 \n" ); document.write( ".26x=520 \n" ); document.write( "x=520/.26 \n" ); document.write( "x=520/.26 \n" ); document.write( "x=$2,000 invested @ 6% \n" ); document.write( "4*2,000=$8,000 invested @ 5% \n" ); document.write( "Proof: \n" ); document.write( ".05*8,000+.06*2,000=520 \n" ); document.write( "400+120=520 \n" ); document.write( "520=520 \n" ); document.write( " |