document.write( "Question 280333: How do you solve for the length and width of a rectangle that has a perimeter of 380 feet and the length is 70 feet less than 3 times the width? \n" ); document.write( "

Algebra.Com's Answer #203735 by pandion(6) $\"\"$ $\"About$

You can put this solution on YOUR website!
let x = L
\n" ); document.write( "y = W
\n" ); document.write( "P = 380 \r
\n" ); document.write( "\n" ); document.write( " $\"2x+%2B+2y+=+380+\"$
\n" ); document.write( " $\"x+=+3y+-+70\"$
\n" ); document.write( " $\"2%283y-70%29+%2B+2y+=+380\"$
\n" ); document.write( " $\"6y-140%2B2y+=+380\"$
\n" ); document.write( " $\"8y-140%2B140+=+380+%2B+140\"$
\n" ); document.write( " $\"8y%2F8=520%2F8\"$
\n" ); document.write( " $\"y=65\"$ \n" ); document.write( "

\n" );