document.write( "Question 280270: The area of a rectangle is 165 ft (2)squared. The length of the rectangle is 4 feet longer than the width. Find the length and width. I need to know the equation and how to solve. \n" ); document.write( "
Algebra.Com's Answer #203694 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The area of a rectangle is 165 ft (2)squared. The length of the rectangle is 4 feet longer than the width. Find the length and width. I need to know the equation and how to solve. \n" ); document.write( "---- \n" ); document.write( "Let the width be \"x\": \n" ); document.write( "Then the length is \"x+4\" \n" ); document.write( "-------------- \n" ); document.write( "Area = x(x+4) \n" ); document.write( "165 = x^2+4x \n" ); document.write( "--- \n" ); document.write( "x^2 + 4x - 165 = 0 \n" ); document.write( "Quadratic formula: \n" ); document.write( "x = [-4 +- sqrt(16-4*-165)]/2 \n" ); document.write( "x = [-4 +- sqrt(676)]/2 \n" ); document.write( "x = [-4 +- 26]/2 \n" ); document.write( "Positive solution: \n" ); document.write( "x = [22/2] \n" ); document.write( "x = 11 ft. (width) \n" ); document.write( "x+4 = 15 ft (length) \n" ); document.write( "=========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |