document.write( "Question 280270: The area of a rectangle is 165 ft (2)squared. The length of the rectangle is 4 feet longer than the width. Find the length and width. I need to know the equation and how to solve. \n" ); document.write( "
Algebra.Com's Answer #203694 by stanbon(75887)\"\" \"About 
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The area of a rectangle is 165 ft (2)squared. The length of the rectangle is 4 feet longer than the width. Find the length and width. I need to know the equation and how to solve.
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\n" ); document.write( "Let the width be \"x\":
\n" ); document.write( "Then the length is \"x+4\"
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\n" ); document.write( "Area = x(x+4)
\n" ); document.write( "165 = x^2+4x
\n" ); document.write( "---
\n" ); document.write( "x^2 + 4x - 165 = 0
\n" ); document.write( "Quadratic formula:
\n" ); document.write( "x = [-4 +- sqrt(16-4*-165)]/2
\n" ); document.write( "x = [-4 +- sqrt(676)]/2
\n" ); document.write( "x = [-4 +- 26]/2
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = [22/2]
\n" ); document.write( "x = 11 ft. (width)
\n" ); document.write( "x+4 = 15 ft (length)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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