document.write( "Question 280196: A certain type of thermal bettery for an airplane navigation device backup power has a mean life of 300 hours with a standard deviation of 15 hours. What proportion of these batteries can be expected to have lives of 322 hours or less? Assume a normal distribution of backup power devices lives.\r
\n" ); document.write( "\n" ); document.write( "I'm so confused about what I am supposed to do. Here is what I have tried:\r
\n" ); document.write( "\n" ); document.write( "15+300/322= 5130/322=15.9
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Algebra.Com's Answer #203662 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A certain type of thermal bettery for an airplane navigation device backup power has a mean life of 300 hours with a standard deviation of 15 hours. What proportion of these batteries can be expected to have lives of 322 hours or less? Assume a normal distribution of backup power devices lives.
\n" ); document.write( "I'm so confused about what I am supposed to do. Here is what I have tried:
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\n" ); document.write( "To get unconfused:
\n" ); document.write( "Sketch a normal curve.
\n" ); document.write( "Put 300 at the middle of the x-axis under the curve.
\n" ); document.write( "Put 15 under the 300 just to remind yourself that 15 is the std.
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\n" ); document.write( "Mark 322 at an apporiate point on the x-axis.
\n" ); document.write( "Shade the area under the curve and to the left of 322.
\n" ); document.write( "That shaded area is the answer to your problem.
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\n" ); document.write( "Find the z-value of 322:
\n" ); document.write( "z(322)= (322-300)/15 = 1.467
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\n" ); document.write( "The following you just have to understand.
\n" ); document.write( "Use your z-chart or your calculator to get:
\n" ); document.write( "P(x < 322) = P(z < 1.467) = 0.9288
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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