document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33974>Question 33974</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 90% acid is to be added to a 15% solution to get 18 liters of a 25% solution.  What amounts of each should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20361 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20361\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the amount of the 90% solution.<BR>\n" );
document.write( "So how much of the 15% solution is there? Answer is 18-x\r<BR>\n" );
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document.write( "and BEFORE = AFTER\r<BR>\n" );
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document.write( "So,<BR>\n" );
document.write( "BEFORE: 0.90x + 0.15(18-x)<BR>\n" );
document.write( "AFTER: 0.25*18\r<BR>\n" );
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document.write( "--> 0.90x + 0.15(18-x) = 0.25*18<BR>\n" );
document.write( "0.90x + 2.7 - 0.15x = 4.5<BR>\n" );
document.write( "0.75x + 2.7 = 4.5<BR>\n" );
document.write( "0.75x = 1.8<BR>\n" );
document.write( "x = 2.4 litres\r<BR>\n" );
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document.write( "so, 2.4 litres of the 90% solution and 15.6 litres of the 15% solution\r<BR>\n" );
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document.write( "jon.<BR>\n" );
document.write( " </SPAN>\n" );
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