document.write( "Question 33989: 2 log(x+2)+log4 = log x + 4 log3 \n" ); document.write( "
Algebra.Com's Answer #20359 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! i assume that the logs are all base10? If so,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2log(x+2)+log4 = log x + 4 log3 \n" ); document.write( "2log(x+2) = log x + 4 log3 - log4 \n" ); document.write( "2log(x+2) - log x = 4 log3 - log4 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, raise both terms to power 10, to cancel the logs: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is just a simple quadratic now, to either factorise if you can spot it or use the quadratic formula if not.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Working this through gives x=16 or x=0.25\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon. \n" ); document.write( " \n" ); document.write( " |