document.write( "Question 33989: 2 log(x+2)+log4 = log x + 4 log3 \n" ); document.write( "
Algebra.Com's Answer #20359 by longjonsilver(2297)\"\" \"About 
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i assume that the logs are all base10? If so,\r
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\n" ); document.write( "\n" ); document.write( "2log(x+2)+log4 = log x + 4 log3
\n" ); document.write( "2log(x+2) = log x + 4 log3 - log4
\n" ); document.write( "2log(x+2) - log x = 4 log3 - log4
\n" ); document.write( "\"+log%28x%2B2%29%5E2+-+log+x+=+log3%5E4+-+log4+\"
\n" ); document.write( "\"+log%28%28x%2B2%29%5E2%2Fx%29+=+log%283%5E4%2F4%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Now, raise both terms to power 10, to cancel the logs:
\n" ); document.write( "\"+%28x%2B2%29%5E2%2Fx+=+3%5E4%2F4+\"
\n" ); document.write( "\"+%28x%2B2%29%5E2%2Fx+=+81%2F4+\"
\n" ); document.write( "\"+4%28x%2B2%29%5E2+=+81x+\"
\n" ); document.write( "\"+4%28x%5E2%2B4x%2B4%29+=+81x+\"
\n" ); document.write( "\"+4x%5E2%2B16x%2B16+=+81x+\"
\n" ); document.write( "\"+4x%5E2-65x%2B16+=+0+\"\r
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\n" ); document.write( "\n" ); document.write( "This is just a simple quadratic now, to either factorise if you can spot it or use the quadratic formula if not.\r
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\n" ); document.write( "\n" ); document.write( "\"+x+=+%28-b+%2B-+sqrt%28b%5E2-4ac%29%29%2F%282a%29+\"
\n" ); document.write( "\"+x+=+%28-%28-65%29+%2B-+sqrt%28%28-65%29%5E2-4%284%29%2816%29%29%29%2F%282%284%29%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Working this through gives x=16 or x=0.25\r
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\n" ); document.write( "\n" ); document.write( "jon.
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