document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=280134>Question 280134</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (49/9)^-3/2<BR>\n" );
document.write( "pleeease help me understand this problem!  :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #203577 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=203577\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> minus exponent means inverse<BR>\n" );
document.write( "so 10^(-1) means 1/10<BR>\n" );
document.write( "10^3=10*10*10<BR>\n" );
document.write( "100^1/2 means take the square  (2) root<BR>\n" );
document.write( "so we have (1/49/9)3/2<BR>\n" );
document.write( "(9/49) ^3/2<BR>\n" );
document.write( "take the square root<BR>\n" );
document.write( "(3/7)^3<BR>\n" );
document.write( "cube it<BR>\n" );
document.write( "3*3*3/7*7*7<BR>\n" );
document.write( "27/343<BR>\n" );
document.write( " </SPAN>\n" );
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