document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=280011>Question 280011</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log of 1/16 in base 1/8 = x<BR>\n" );
document.write( "what does x equal? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #203538 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=203538\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log of 1/16 in base 1/8 = x<BR>\n" );
document.write( "what does x equal?\r<BR>\n" );
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document.write( "The change of base formula says:\r<BR>\n" );
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document.write( "1.) log base b (x) = (log base d (x))/(log base d (b))\r<BR>\n" );
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document.write( "Note that 1/8 = (1/2)^3 and that 1/16 = (1/2)^4.  Letting d = 1/2 in 1.) above we have:\r<BR>\n" );
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document.write( "x = log base 1/8 (1/16) = (log base 1/2 (1/16))/(log base 1/2 (1/8))<BR>\n" );
document.write( "x = 4/3\r<BR>\n" );
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document.write( " </SPAN>\n" );
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