document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=280009>Question 280009</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve the system using addition/elimination method and show work? <BR>\n" );
document.write( "3x+2y=14<BR>\n" );
document.write( "3x-2y+10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #203533 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=203533\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do I solve the system using addition/elimination method and show work? <BR>\n" );
document.write( "1.) 3x+2y=14<BR>\n" );
document.write( "2.) 3x-2y+10\r<BR>\n" );
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document.write( "We can subtract the corresponding sides of the two equations above to eliminate x as follows: \r<BR>\n" );
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document.write( "(3x+2y)-(3x-2y) = 14-10<BR>\n" );
document.write( "3x-3x + 2y+2y = 4<BR>\n" );
document.write( "4y = 4<BR>\n" );
document.write( "y = 1\r<BR>\n" );
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document.write( "Now substitute 1 for y in either 1.) or 2.) and solve for x.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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