document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33961>Question 33961</A>: <I><SPAN STYLE=\"word-break: break-all;\"> directions:solve problems using two unkowns and a system of two equations.\r<BR>\n" );
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document.write( "the diffrence of two numbers is -1. if twice the first number is added to three times the second number, the result is 13. what are the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20352 by </B><A HREF=/tutors/aboutme.mpl?userid=fanism><B>fanism(39)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fanism><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20352\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the first # be x and the second # be y<BR>\n" );
document.write( "x - y = -1 -- eq 1<BR>\n" );
document.write( "2x + 3y = 13 -- eq 2\r<BR>\n" );
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document.write( "multifply eq 1 by 2, yields<BR>\n" );
document.write( "2x - 2y = -2 -- eq 3\r<BR>\n" );
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document.write( "now, take eq2 - eq3, u will get<BR>\n" );
document.write( "0 - 5y = 15<BR>\n" );
document.write( "y = -3\r<BR>\n" );
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document.write( "sub y = -3 into any of the above equation, <BR>\n" );
document.write( "let use eq1, u will get<BR>\n" );
document.write( "x - (-3) = -1<BR>\n" );
document.write( "x + 3 = -1<BR>\n" );
document.write( "x = -4 </SPAN>\n" );
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