document.write( "Question 280099: train A is traveling at 60 mph and train B at 80 mph. train A passes the station at 810 and train B at 825 at what time will train B catch train A? \n" ); document.write( "
Algebra.Com's Answer #203518 by josmiceli(19441)\"\" \"About 
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Train A has a 15 minute head start over B if you consider
\n" ); document.write( "the station as the starting point. In that time, A has gone
\n" ); document.write( "\".25%2A60+=+15\" miles.
\n" ); document.write( "Assume I have a stopwatch. I'll start it when B reaches the station
\n" ); document.write( "If I stop it when B catches A, both trains will have been moving
\n" ); document.write( "for the same length of time, which I'll call \"t\"
\n" ); document.write( "given:
\n" ); document.write( "\"v%5Ba%5D+=+60\" mi/hr
\n" ); document.write( "\"v%5Bb%5D+=+80\" mi/hr
\n" ); document.write( "\"d%5Bb%5D+=+d%5Ba%5D+%2B+15\" mi
\n" ); document.write( "----------------
\n" ); document.write( "Now I can write equations for both trains
\n" ); document.write( "\"d%5Ba%5D+=+60t\"
\n" ); document.write( "\"d%5Ba%5D+%2B+15+=+80t\"
\n" ); document.write( "By substitution,
\n" ); document.write( "\"60t+%2B+15+=+80t\"
\n" ); document.write( "\"20t+=+15\"
\n" ); document.write( "\"t+=+3%2F4\" hr
\n" ); document.write( "Train B will catch train A in 45 min, or at 8:25 + 45 = 9:05
\n" ); document.write( "check answer:
\n" ); document.write( "\"d%5Ba%5D+=+60t\"
\n" ); document.write( "\"d%5Ba%5D+=+60%2A%283%2F4%29\"
\n" ); document.write( "\"d%5Ba%5D+=+45\" mi
\n" ); document.write( "and
\n" ); document.write( "\"d%5Ba%5D+%2B+15+=+80t\"
\n" ); document.write( "\"d%5Ba%5D+%2B+15+=+80%2A%283%2F4%29\"
\n" ); document.write( "\"d%5Ba%5D+%2B+15+=+60\"
\n" ); document.write( "\"d%5Ba%5D+=+45\" mi
\n" ); document.write( "OK
\n" ); document.write( "
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