document.write( "Question 280099: train A is traveling at 60 mph and train B at 80 mph. train A passes the station at 810 and train B at 825 at what time will train B catch train A? \n" ); document.write( "
Algebra.Com's Answer #203518 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Train A has a 15 minute head start over B if you consider \n" ); document.write( "the station as the starting point. In that time, A has gone \n" ); document.write( " \n" ); document.write( "Assume I have a stopwatch. I'll start it when B reaches the station \n" ); document.write( "If I stop it when B catches A, both trains will have been moving \n" ); document.write( "for the same length of time, which I'll call \n" ); document.write( "given: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "---------------- \n" ); document.write( "Now I can write equations for both trains \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "By substitution, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Train B will catch train A in 45 min, or at 8:25 + 45 = 9:05 \n" ); document.write( "check answer: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " |